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Answers test examination

RPO THK-basic

1 A 11 B 21 B 31 C
2 A 12 B 22 A 32 B
3 A 13 A 23 C 33 C
4 D 14 A 24 D 34 D
5 B 15 D 25 C 35 B
6 B 16 B 26 A 36 D
7 A 17 A 27 A 37 D
8 C 18 B 28 D 38 D
9 C 19 B 29 D 39 C
10 D 20 A 30 C 40 C

Evaluation of question 41:

Reading figure A at 90 kV and 3 mm aluminum –› 0.08 mSv/mAs at 1 meter
The mAs value = 6 mA × 0.3 s = 1.8 mAs
The equivalent dose at 1 meter = 0.08 mSv/mAs × 1.8 mAs = 0.14 mSv
The equivalent dose at 35 cm = 0.35 m -> 0.14 mSv × (1 m / 0.35 m)2 = 1.2 mSv

Evaluation of question 42:

Reading figure A at 90 kV and 3 mm aluminum –› 0.08 mSv/mAs at 1 meter
The equivalent dose for 2000 / 2 = 1000 photos –› 1000 × 0.08 mSv/mAs × 1.5 mAs = 120 mSv at 1 meter
The equivalent dose at 3 meters = 120 mSv × (1 m / 3 m)2 = 13 mSv
Reading figure B at 90 kV and 11 mm glass –› T = 0.3
The annual effective dose on the street = 13 mSv × 0.3 = 4 mSv
Annual limit in case of registration = 10 µSv –› insufficient shielding

Last modified:07 February 2019 1.54 p.m.
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